A uniform rod of length 2 m is pivoted at one end. If the rod is in equilibrium under its own weight

Question

A uniform rod of length 2 m is pivoted at one end. If the rod is in equilibrium under its own weight, what is the distance of its center of mass from the pivot point?

Professor PC Thomas Classes · Answer

For a uniform rod, the centre of mass is located at its geometric center. Distance from pivot = $2/2 = 1.0$ m.