If the size of an atom $(\sim 1 \AA)$ is enlarged to the size of the earth $\left(-10^7\right)$ what

Question

If the size of an atom $(\sim 1 \AA)$ is enlarged to the size of the earth $\left(-10^7\right)$ what would be the size of the nucleus $\left(10^{-15} \mathrm{~m}\right)$ ?

Professor PC Thomas Classes · Answer

Scale factor $= 10^7 / 10^{-10} = 10^{17}$. Nucleus size $= 10^{-15} 	imes 10^{17} = 10^2 = 100$ m.