For a general chemical equilibria $\mathrm{AX}_1(\mathrm{~g}) \rightleftharpoons \mathrm{AX}_2(\math

Question

For a general chemical equilibria $\mathrm{AX}_1(\mathrm{~g}) \rightleftharpoons \mathrm{AX}_2(\mathrm{~g})+1 / 2 \mathrm{X}_2(\mathrm{~g})$, the equilibrium constant is $\mathrm{K}_c$; The equilibrium constant for the reaction $2 \mathrm{AX}_2(\mathrm{~g})+\mathrm{X}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AX}_3$ (g) will be

Professor PC Thomas Classes · Answer

Reversing and multiplying reaction by 2 transforms $K_c$ to $(1/K_c)^2$.