The number of moles of $\mathrm{KMnO}_4$ required to reduce one mole of KI in alkaline medium is

Question

Professor PC Thomas Classes · Answer

In alkaline medium, $\mathrm{KMnO}_4$ oxidizes KI to $\mathrm{KIO}_3$. $2\mathrm{KMnO}_4 + \mathrm{KI} + \mathrm{H}_2\mathrm{O} \rightarrow 2\mathrm{MnO}_2 + \mathrm{KIO}_3 + 2\mathrm{KOH}$. Moles = 2.