The area enclosed within the curve $|x|+|y|=2$ is

Question

Professor PC Thomas Classes · Answer

A square with vertices at $(\pm 2, 0)$ and $(0, \pm 2)$. Diagonals $= 4$. Area $= \frac{1}{2} d_1 d_2 = \frac{1}{2}(4)(4) = 8$.