Three normals are drawn to the parabola $y^2=x$ through the point $(a, 0)$. Then

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Professor PC Thomas Classes · Answer

For $y^2=4ax$ (here $4A=1 \Rightarrow A=1/4$), three normals from $(h,0)$ exist if $h > 2A$. So $a > 2(1/4) = 1/2$.