In a triangle $A B C, b=\sqrt{3}, c=2$ and $\sin B=\frac{3}{4}$, then $C$ is equal to

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Professor PC Thomas Classes · Answer

Using Sine Rule: $\frac{\sin C}{c} = \frac{\sin B}{b} \Rightarrow \sin C = \frac{2 	imes (3/4)}{\sqrt{3}} = \frac{\sqrt{3}}{2} \Rightarrow C = 60^{\circ}$.