If $\omega
eq 1$ is the complex cube root of unity and matrix $H=\left[\begin{array}{cc}\omega & 0

Question

If $\omega 
eq 1$ is the complex cube root of unity and matrix $H=\left[\begin{array}{cc}\omega & 0 \ 0 & \omega\end{array}ight]$, then $H^{70}$ is equal to

Professor PC Thomas Classes · Answer

$H^3 = I$. $H^{70} = (H^3)^{23} \cdot H^1 = I \cdot H = H$.