The moment of inertia of a sphere about a diameter of a sphere is $\frac{2}{5} M R^2, M$ is the mass

Question

The moment of inertia of a sphere about a diameter of a sphere is $\frac{2}{5} M R^2, M$ is the mass and $R$ is the radius, then the moment of inertia of a sphere about a tangent to the sphere is

Professor PC Thomas Classes · Answer

Parallel axis theorem: $I = I_{cm} + MR^2 = \frac{2}{5}MR^2 + MR^2 = \frac{7}{5}MR^2$.