A position dependent force $F=\left(7-2 x+3 x^2\right) \mathrm{N}$, acts on a small body of mass 2 k

Question

A position dependent force $F=\left(7-2 x+3 x^2\right) \mathrm{N}$, acts on a small body of mass 2 kg and displaces it from $x=0$ to $x=5 \mathrm{~m}$. Work done is

Professor PC Thomas Classes · Answer

$W = \int F dx = [7x - x^2 + x^3]_0^5 = 35 - 25 + 125 = 135 	ext{ J}$.