The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of 14 mV and

Question

The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of 14 mV and 6 mV respectively is

Professor PC Thomas Classes · Answer

Modulation index $m = \frac{V_{max} - V_{min}}{V_{max} + V_{min}} = \frac{14 - 6}{14 + 6} = \frac{8}{20} = 0.4$.