A beam of protons with speed $4 imes 10^5 \mathrm{~ms}^{-1}$ enters a uniform magnetic field of 0.

Question

A beam of protons with speed $4 	imes 10^5 \mathrm{~ms}^{-1}$ enters a uniform magnetic field of 0.3 T at an angle of $60^{\circ}$ to the magnetic field. Then the pitch of the resulting helical path of protons is close to [Mass of the protom $=1.67 	imes 10^{-27} \mathrm{~kg}$, charge of the protom $=1.69 	imes 10^{-19} \mathrm{C}$ ]

Professor PC Thomas Classes · Answer

Force $F = qvB \sin 	heta$.