What is the activation energy for a reaction if its rate doubles when the temperature is raised from

Question

What is the activation energy for a reaction if its rate doubles when the temperature is raised from 200 K to $400 \mathrm{~K} ?\left(\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)$

Professor PC Thomas Classes · Answer

Arrhenius equation: $\ln(k_2/k_1) = \frac{E_a}{R}(\frac{1}{T_1} - \frac{1}{T_2})$.