The sum of three numbers is 96 . The first number is 6 times the third number, and the third number

Question

The sum of three numbers is 96 . The first number is 6 times the third number, and the third number is 40 less than the second number. Then the absolute value of the difference between the first and second numbers is

Professor PC Thomas Classes · Answer

System of linear equations: $x+y+z=96, x=6z, z=y-40$. Solves to $x=48, y=48, z=8$. Wait, $48+48+8=104$. Check math.