If the lines $\frac{x-2}{k}=\frac{y-3}{3}=\frac{z+2}{-1}$ and $\frac{x-2}{8}=\frac{y-3}{6}=\frac{z+2

Question

If the lines $\frac{x-2}{k}=\frac{y-3}{3}=\frac{z+2}{-1}$ and $\frac{x-2}{8}=\frac{y-3}{6}=\frac{z+2}{-2}$ are parallel, then the value of $k$ is

Professor PC Thomas Classes · Answer

Proportional direction ratios for parallel lines.