Two vectors $\vec{a}$ and $\vec{b}$ are acting at $90^{\circ} |\overrightarrow{\mathrm{a}}|=6 \quad|

Question

Two vectors $\vec{a}$ and $\vec{b}$ are acting at $90^{\circ} |\overrightarrow{\mathrm{a}}|=6 \quad|\overrightarrow{\mathrm{~b}}|=8$; then $|\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}|$ is

Professor PC Thomas Classes · Answer

$|\vec{a}+\vec{b}| = \sqrt{6^2 + 8^2} = 10$