A body weights 48 N on the surface of the earth. The gravitational force experienced by the body due

Question

A body weights 48 N on the surface of the earth. The gravitational force experienced by the body due to the earth at a height equal to one-third the radius of the earth from its surface is

Professor PC Thomas Classes · Answer

(d) : Given, $W=48 \mathrm{~N}$ and $h=\frac{R}{3}$\Gravitational force at a height $h$ above the surface of the Earth, \ $ F=\frac{G m M}{(R+h)^2} $ or $F=\frac{G\left(\frac{W}{g}ight) 	imes M}{\left(R+\frac{R}{3}ight)^2} \\quad\left[\becauseight.$ Weight, $W=m g$ \ or $\left.m=\frac{W}{g}ight]$ or $F=\frac{G 	imes 48 	imes M 	imes 9}{g 	imes 16 R^2}$ \Substituting, $g=\frac{G M}{R^2}$, we get $ F=\frac{48 	imes 9}{16}=27 \mathrm{~N} $