The value of electric potential at a distance of 9 cm from the point charge $4 imes 10^{-7} \mathr

Question

The value of electric potential at a distance of 9 cm from the point charge $4 	imes 10^{-7} \mathrm{C}$ is $ 	ext { (Given that } \left.\frac{1}{4 \pi \varepsilon_0}=9 	imes 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}ight) $

Professor PC Thomas Classes · Answer

(d) : $r=9 \mathrm{~cm}=9 	imes 10^{-2} \mathrm{~m}$ \ $ q=4 	imes 10^{-7} \mathrm{C} $ As, $V=\frac{1}{4 \pi \varepsilon_o} \frac{q}{r}=\frac{9 	imes 10^9 	imes 4 	imes 10^{-7}}{9 	imes 10^{-2}}=4 	imes 10^4 \mathrm{~V}$