The terminal voltage of the battery, whose emf is 10 V and internal resistance $1 \Omega$, when conn

Question

The terminal voltage of the battery, whose emf is 10 V and internal resistance $1 \Omega$, when connected through an external resistance of $4 \Omega$ as shown in the figure is

Professor PC Thomas Classes · Answer

(c) : Current in the given circuit 
$ I=\frac{10}{4+1}=\frac{10}{5}=2 \mathrm{~A} $
 Terminal voltage, $V=E-I r=10-2 	imes 1=8 \mathrm{~V}$