$A B$ is a part of an electrical circuit (see figure). The potential difference " $V_A-V_B$ ", at th

Question

$A B$ is a part of an electrical circuit (see figure). The potential difference " $V_A-V_B$ ", at the instant when current $i=2 \mathrm{~A}$ and is increasing at a rate of $1 \mathrm{amp} /$ second

Professor PC Thomas Classes · Answer

b) From the diagram (Using KVL) $$ V_A-L \frac{d i}{d t}-5-2 i=V_B $$ Using, $i=2 \mathrm{~A}, \frac{d i}{d t}=1 \mathrm{~A} / \mathrm{sec}$ and $L=1 \mathrm{H}$, we get $$ V_A-1-5-4=V_B \Rightarrow V_A-V_B=10 \mathrm{~V} $$