In an ideal transformer, the turns ratio is $\frac{N_p}{N_s}=\frac{1}{2}$. The ratio $V_s: V_p$ is e

Question

In an ideal transformer, the turns ratio is $\frac{N_p}{N_s}=\frac{1}{2}$. The ratio $V_s: V_p$ is equal to (the symbols carry their usual meaning)

Professor PC Thomas Classes · Answer

(b) : Here, $\frac{N_p}{N_s}=\frac{1}{2}$ For ideal transformer, $\frac{N_p}{N_s}=\frac{V_p}{V_s}$ $$ \Rightarrow \frac{1}{2}=\frac{V_p}{V_s} \Rightarrow \frac{V_s}{V_p}=\frac{2}{1} $$