The electric field in a plane electromagnetic wave is given by $$ E_z=60 \cos \left(5 x+1.5 imes 1

Question

The electric field in a plane electromagnetic wave is given by $$ E_z=60 \cos \left(5 x+1.5 	imes 10^9 tight) \mathrm{V} / \mathrm{m} . $$ Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field)

Professor PC Thomas Classes · Answer

(c)Given, $E_z=60 \cos \left(5 x+1.5 	imes 10^9 tight) \mathrm{V} / \mathrm{m}$ As, $B_0=\frac{E_0}{c} \Rightarrow B_0=\frac{60}{3 	imes 10^8}=2 	imes 10^{-7} \mathrm{~T}$ \ Since, In an em wave, the direction of wave propagation is along $\vec{E} 	imes \vec{B}$ thus magnetic field will be along $y$-direction \ $	herefore \quad B_y=2 	imes 10^{-7} \cos \left(5 x+1.510^9 tight) \mathrm{J}$