$\quad{ }_{82}^{290} X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrigh

Question

$\quad{ }_{82}^{290} X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrightarrow{e^{-}} Q$ \ In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are

Professor PC Thomas Classes · Answer

(d) : ${ }_{82}^{290} X \xrightarrow{\alpha}{ }_{80}^{286} Y \xrightarrow{e^{+}}{ }_{79}^{286} Z \xrightarrow{\beta^{-}}{ }_{80}^{286} P \xrightarrow{e^{-}}{ }_{81}^{286} Q$