The graph which shows the variation of $\left(\frac{1}{\lambda^2}\right)$ and its kinetic energy, $E

Question

The graph which shows the variation of $\left(\frac{1}{\lambda^2}\right)$ and its kinetic energy, $E$ is (where $\lambda$ is de-Broglie wavelength of a free particle)

Professor PC Thomas Classes · Answer

(c) : de Broglie wavelength of electron, \ $ \lambda_e=\frac{12.27 \AA}{\sqrt{V(	ext { in } \mathrm{V})}}  \ $ Here, $V=10000 \mathrm{~V}$ \ $ 	herefore \quad \lambda_e=\frac{12.27}{\sqrt{10000}} 	imes 10^{-10} \mathrm{~m}=12.27 	imes 10^{-12} \mathrm{~m} $