Match List I with List II \ Choose the correct answer from the options given below.

Question

Professor PC Thomas Classes · Answer

(b) : Wavelength of spectral lines of hydrogen is given by \ $ \frac{1}{\lambda}=R\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}ight] $ \ For $n_2=3$ to $n_1=2$ \ $ \frac{1}{\lambda}=1.09 	imes 10^7\left[\frac{1}{(2)^2}-\frac{1}{(3)^2}ight] $ \ $ \begin{aligned} & \lambda=656.3 \mathrm{~nm} \ & \mathrm{~A} ightarrow \mathrm{III} \end{aligned} $ \ For $n_2=4$ to $n_1=2$ $ \ \frac{1}{\lambda}=1.09 	imes 10^7\left[\frac{1}{(2)^2}-\frac{1}{(4)^2}ight] \Rightarrow \lambda=486.1 \mathrm{~nm} $ \ $ \mathrm{B} ightarrow \mathrm{IV} $ For $n_2=5$ to $n_1=2$ $\ \frac{1}{\lambda}=1.09 	imes 10^7\left[\frac{1}{(2)^2}-\frac{1}{(5)^2}ight] \Rightarrow \lambda=434.1  \mathrm{~nm} $ \ For $n_2=6$ to $n_1=2$ $ \frac{1}{\lambda}=1.09 	imes 10^7\left[\frac{1}{(2)^2}-\frac{1}{(6)^2}ight] \Rightarrow \lambda=410.2 \mathrm{~nm} $ \ $ \mathrm{D} ightarrow \mathrm{I} $ Option (b) is correct.