A $10 \mu \mathrm{~F}$ capacitor is connected to a $210 \mathrm{~V}, 50 \mathrm{~Hz}$ source as show

Question

A $10 \mu \mathrm{~F}$ capacitor is connected to a $210 \mathrm{~V}, 50 \mathrm{~Hz}$ source as shown in figure. The peak current in the circuit is nearly ( $\pi=3.14$ )

Professor PC Thomas Classes · Answer

(b) : 
$V_{r m s}=210 \mathrm{~V}, f=50 \mathrm{~Hz}, C=10 \mu \mathrm{~F}$
$X_C=\frac{1}{2 \pi f C}=\frac{1}{2 	imes 3.14 	imes 50 	imes 10 	imes 10^{-6}}$
$=318.47 \Omega$
$I_{r m s}=\frac{V_{r m s}}{X_C}=\frac{210}{318.47}=0.6594 \mathrm{~A}$