The amount of glucose required to prepare 250 mL of $M / 20$ aqueous solution is (Molar mass of gluc

Question

The amount of glucose required to prepare 250 mL of $M / 20$ aqueous solution is (Molar mass of glucose : $180 \mathrm{~g} \mathrm{~mol}^{-1}$ )

Professor PC Thomas Classes · Answer

$\begin{aligned} & 	ext { (a) : Molarity }=\frac{w 	imes 1000}{M 	imes V(\mathrm{~mL})} ; \frac{1}{20}=\frac{w 	imes 1000}{180 	imes 250} \ & w=\frac{180 	imes 250}{20 	imes 1000} ; w=2.25 \mathrm{~g}\end{aligned}$