For the following reaction at 300 K ,\ $A_{2(g)}+3 B_{2(g)} \longrightarrow 2 A B_{3(g)}$ \ The e

Question

For the following reaction at 300 K ,\  $A_{2(g)}+3 B_{2(g)} \longrightarrow 2 A B_{3(g)}$ \ The enthalpy change is +15 kJ , then the internal energy change is

Professor PC Thomas Classes · Answer

(a) : If $n_p<n_r$ and $\Delta n_g=n_p-n_r=-\mathrm{ve}$; then, $ \Delta H<\Delta E $ As $\Delta H=+15 \mathrm{~kJ}$ or $+15,000 \mathrm{~J}$, the only possible answer from the given options is 19988.4 J . $