A car travels 200 km on a straight line path. It travels first 100 km with speed of $40 \mathrm{~km}

Question

A car travels 200 km on a straight line path. It travels first 100 km with speed of $40 \mathrm{~km} / \mathrm{h}$ and next 100 km with a speed of $60 \mathrm{~km} / \mathrm{h}$. The average a speed of the car in this process is

Professor PC Thomas Classes · Answer

Average speed $V_{avg} = \frac{2 V_1 V_2}{V_1 + V_2} = \frac{2(40)(60)}{40+60} = \frac{4800}{100} = 48 \mathrm{km/h}$.