A body projected with a speed $u$ an angle $30^{\circ}$ with horizontal its horizontal range is 40 m

Question

A body projected with a speed $u$ an angle $30^{\circ}$ with horizontal its horizontal range is 40 m . If this body is projected with same speed u but at angle $60^{\circ}$ with horizontal, the horizontal range in this case will be

Professor PC Thomas Classes · Answer

Horizontal range $R = \frac{u^2 \sin 2	heta}{g}$. Since $30^{\circ}$ and $60^{\circ}$ are complementary angles ($30^{\circ}+60^{\circ}=90^{\circ}$), their horizontal ranges are equal. Range = $40 \mathrm{m}$.