A body thrown vertically up with a speed $40 \mathrm{~m} / \mathrm{s}$. The time taken to reach high

Question

A body thrown vertically up with a speed $40 \mathrm{~m} / \mathrm{s}$. The time taken to reach highest point is $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$

Professor PC Thomas Classes · Answer

At highest point, $v=0$. Using $v = u - gt \implies 0 = 40 - 10t \implies t = 4 \mathrm{s}$.