Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of

Question

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of the oscillation is 0.05 s and the velocity of the wave is $300 \mathrm{~m} / \mathrm{s}$. Then the phase difference between the oscillations at the two points is

Professor PC Thomas Classes · Answer

Wavelength $\lambda = vT = 300 	imes 0.05 = 15 \mathrm{~m}$. Path difference $\Delta x = 5 \mathrm{~m}$. Phase difference $\Delta \phi = \frac{2\pi}{\lambda}\Delta x = \frac{2\pi}{15} 	imes 5 = \frac{2\pi}{3}$.