A wheel having moment of inertia $2 \mathrm{~kg} \mathrm{~m}^2$ about its axis, rotates at 50 rpm ,

Question

A wheel having moment of inertia $2 \mathrm{~kg} \mathrm{~m}^2$ about its axis, rotates at 50 rpm , about this axis. Then the torque that can stop the wheel in one minute is

Professor PC Thomas Classes · Answer

Initial angular velocity $\omega_0 = \frac{2\pi N}{60} = \frac{5\pi}{3} \mathrm{~rad/s}$. Torque $	au = I\alpha = I\frac{\omega_0}{t} = 2 	imes \frac{5\pi/3}{60} = \frac{\pi}{18} \mathrm{~N\cdot m}$.