The molar conductances of $\mathrm{NaCl}, \mathrm{HCl}$ and $\mathrm{CH}_3 \mathrm{COONa}$ at infini

Question

The molar conductances of $\mathrm{NaCl}, \mathrm{HCl}$ and $\mathrm{CH}_3 \mathrm{COONa}$ at infinite dilution are 126.45 , 426.16 and $91 \mathrm{Ohm}^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ respectively. The molar conductance of acetic acid at infinite dilution is

Professor PC Thomas Classes · Answer

By Kohlrausch's law $\Lambda^\circ_{\mathrm{CH_3COOH}} = \Lambda^\circ_{\mathrm{CH_3COONa}} + \Lambda^\circ_{\mathrm{HCl}} - \Lambda^\circ_{\mathrm{NaCl}} = 91 + 426.16 - 126.45 = 390.71 \mathrm{~ohm^{-1} cm^2 mol^{-1}}$.