The hydrogen electrode is dipped in a solution of $\mathrm{pH}=3$ at $25^{\circ} \mathrm{C}$, the po

Question

The hydrogen electrode is dipped in a solution of $\mathrm{pH}=3$ at $25^{\circ} \mathrm{C}$, the potential of the cell would be (the value of $\frac{2.303 R T}{F}=0.059 \mathrm{~V}$ )

Professor PC Thomas Classes · Answer

$E = E^\circ - \frac{0.059}{n} \log[H^+]^{-1} = 0 - 0.059 	imes 3 = -0.177 \mathrm{~V}$.