The area between the curve $y=x^2-2 x$ and the straight line $y=x$, is

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Professor PC Thomas Classes · Answer

Intersection points: $x^2-2x = x \Rightarrow x = 0, 3$. Area $= \int_0^3 (x - (x^2-2x))dx = \int_0^3 (3x-x^2)dx = \frac{9}{2}$.