Let $\vec{a}$ and $\vec{b}$ be two vectors such that $|\vec{a} \cdot \vec{b}|=\sqrt{3}|\vec{a} ime

Question

Let $\vec{a}$ and $\vec{b}$ be two vectors such that $|\vec{a} \cdot \vec{b}|=\sqrt{3}|\vec{a} 	imes \vec{b}|$. Then $	heta$ is

Professor PC Thomas Classes · Answer

$|ab\cos	heta| = \sqrt{3}|ab\sin	heta| \Rightarrow 	an	heta = \frac{1}{\sqrt{3}} \Rightarrow 	heta = \frac{\pi}{6}$.