$\left|\begin{array}{ccc}1 & 27 & 27^3 \ 1 & 28 & 28^3 \ 1 & 29 & 29^3\end{array} ight|=$

Question

$\left|\begin{array}{ccc}1 & 27 & 27^3 \ 1 & 28 & 28^3 \ 1 & 29 & 29^3\end{array}ight|=$

Professor PC Thomas Classes · Answer

The determinant uses $(x-y)(y-z)(z-x)(x+y+z)$. $1 	imes 1 	imes 2 	imes (27+28+29) = 168$.