Two resistances $R_1=10.0 \Omega \pm 0.1 \Omega$ and $R_2=5.0 \pm 0.1 \Omega$ are connected in paral

Question

Two resistances $R_1=10.0 \Omega \pm 0.1 \Omega$ and $R_2=5.0 \pm 0.1 \Omega$ are connected in parallel. Then \% of error in the resultant value of $R$ is

Professor PC Thomas Classes · Answer

Error propagates as $\frac{\Delta R}{R^2} = \frac{\Delta R_1}{R_1^2} + \frac{\Delta R_2}{R_2^2}$ yielding $4.3\%$.