A bar magnet of magnetic moment $M$ and moment of inertia $I$ is freely suspended such that the magn

Question

A bar magnet of magnetic moment $M$ and moment of inertia $I$ is freely suspended such that the magnetic axial line is in the direction of the magnetic meridian. If the magnetic induction of earth's horizontal field is $B_H$ and the magnet is displaced by a very small angle $	heta$, angular acceleration is

Professor PC Thomas Classes · Answer

Torque $= MB_H 	heta$. Angular acceleration $\alpha = \frac{MB_H 	heta}{I}$.