If $1, \omega$ and $\omega^2$ are the cube roots of unity, then \ $\left(1-\omega+\omega^2 ight)\

Question

If $1, \omega$ and $\omega^2$ are the cube roots of unity, then  \ $\left(1-\omega+\omega^2ight)\left(1-\omega^2+\omega^4ight)\left(1-\omega^4+\omega^8ight)\left(1-\omega^8+\omega^{16}ight) \ldots$ upto $2 n$ factors are

Professor PC Thomas Classes · Answer

Grouping roots of unity patterns yields $2^{2n}$.