$ an ^{-1}\left(\frac{1+\sqrt{3}}{3+\sqrt{3}} ight)+\sec ^{-1}\left(\sqrt{\frac{8+4 \sqrt{3}}{6+3

Question

$	an ^{-1}\left(\frac{1+\sqrt{3}}{3+\sqrt{3}}ight)+\sec ^{-1}\left(\sqrt{\frac{8+4 \sqrt{3}}{6+3 \sqrt{3}}}ight)$ is equal to

Professor PC Thomas Classes · Answer

Trigonometric simplification leads to the angle $\frac{\pi}{3}$.