For the Daniel cell $\mathrm{Zn}\left|\mathrm{Zn}^{2+} \mathrm{HCu}^{2+} \mathrm{Cu}\right|$ with $\

Question

For the Daniel cell $\mathrm{Zn}\left|\mathrm{Zn}^{2+} \mathrm{HCu}^{2+} \mathrm{Cu}\right|$ with $\mathrm{E}^{\circ}$ cell $=1.1 \mathrm{~V}$ the application of opposite potential greater than 1.1 V results in

Professor PC Thomas Classes · Answer

Applying an opposing potential $> E_{cell}$ reverses the cell reaction, causing oxidation of Cu and reduction of $Zn^{2+}$.