Let $a, b, c, d, e$ be five consecutive tenms in an arithmetic sequence and suppose $a+b+c+d+c=30$.

Question

Let $a, b, c, d, e$ be five consecutive tenms in an arithmetic sequence and suppose $a+b+c+d+c=30$. Which of the following can be found?

Professor PC Thomas Classes · Answer

Symmetric AP sum assigns $a+b+c+d+e = 5c = 30$, trivially pinpointing $c=6$.