The angle between the planes $2 x-y+z=6, x+y+2 z=3$ is

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Professor PC Thomas Classes · Answer

Angle bounded by normals $\vec{n_1}$ and $\vec{n_2}$. $\cos	heta = \frac{n_1 \cdot n_2}{|n_1||n_2|} = \frac{3}{6} = \frac{1}{2}$, dictating $	heta = \pi/3$.