The equilibrium $2 \mathrm{CuI} \rightleftharpoons \mathrm{Cu}^{0}+\mathrm{Cu}^{\mathrm{II}}$ in aqu

Question

The equilibrium $2 \mathrm{CuI} ightleftharpoons \mathrm{Cu}^{0}+\mathrm{Cu}^{\mathrm{II}}$ in aqueous medium at $25^{\circ} \mathrm{C}$ shifts towards the left in the presence of\

Professor PC Thomas Classes · Answer

(b, c, d) : $\mathrm{Cu}^{2+}$ ion will react with $\mathrm{CN}^{-}$and $\mathrm{SCN}^{-}$forming $\left[\mathrm{Cu}(\mathrm{CN})_{4}ight]^{3-}$ and $\left[\mathrm{Cu}(\mathrm{SCN})_{4}ight]^{3-}$ leading the reaction to the backward direction.\ $\mathrm{Cu}^{2+}+2 \mathrm{CN}^{-} \longrightarrow \mathrm{Cu}(\mathrm{CN})_{2}$\ $2 \mathrm{Cu}(\mathrm{CN})_{2} \longrightarrow 2 \mathrm{CuCN}+(\mathrm{CN})_{2}$\ $\mathrm{CuCN}+3 \mathrm{CN}^{-} \longrightarrow\left[\mathrm{Cu}(\mathrm{CN})_{4}ight]^{3-}$\ $\mathrm{Cu}^{2+}+4 \mathrm{SCN}^{-} \longrightarrow\left[\mathrm{Cu}(\mathrm{SCN})_{4}ight]^{3-}$\ $\mathrm{Cu}^{2+}$ also combines with $\mathrm{Cl}^{-}$to form $\mathrm{CuCl}_{2}$ which reacts with Cu to produce CuCl pushing the reaction in the backward direction.\ $\mathrm{CuCl}_{2}+\mathrm{Cu} \longrightarrow 2 \mathrm{CuCl} \downarrow$