In nitroprusside ion, the iron and NO exist as $\mathrm{Fe}^{I I}$ and $\mathrm{NO}^{+}$rather than

Question

In nitroprusside ion, the iron and NO exist as $\mathrm{Fe}^{I I}$ and $\mathrm{NO}^{+}$rather than $\mathrm{Fe}^{I I I}$ and NO . These forms can be differentiated by\

Professor PC Thomas Classes · Answer

(c) : Magnetic moment $\mu$ is given by\ $\mu=\sqrt{n(n+2)}$ B.M.\ Where $n$ is the number of unpaired electrons.\ Number of unpaired electrons in various species are\ Since they (i.e. ${ }^{+} \mathrm{NO}$ and NO ) have different number of unpaired electrons so they can be differentiated by the measurement of the solid state magnetic moment of nitroprusside ion.\