For the given aqueous reactions, which of the statement(s) is(are) true?\

Question

Professor PC Thomas Classes · Answer

(a, c, d) : \ (a)is correct as in reaction (i), $I^{-}(-1)$ is being oxidised to $\mathrm{I}_{2}(0)$ and $\mathrm{Fe}^{3+}$ is being reduced to $\mathrm{Fe}^{2+}$.\(b)is incorrect as white precipitate is of\ $\mathrm{K}_{2} \mathrm{Zn}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{2}$ or $\mathrm{Zn}_{2}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$\(c)is correct as\ $\mathrm{I}_{3}^{-} \rightleftharpoons \mathrm{I}^{-}+\mathrm{I}_{2}+$ starch $\rightarrow$ Blue colour filtrate\(d)is correct as white precipitate of $\mathrm{K}_{2} \mathrm{Zn}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{2}$ or $\mathrm{Zn}_{2}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$ is soluble in NaOH as\ $\mathrm{Zn}_{2}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]+8 \mathrm{NaOH} \longrightarrow$ $$ 2 \mathrm{Na}_{2}\left[\mathrm{Zn}(\mathrm{OH})_{4}\right]+\underset{\text { Soluble }}{\mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]} $$