Sodium nitrate decomposes above $800^{\circ} \mathrm{C}$ to give\

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(a,b,d); When heated above $500^{\circ} \mathrm{C}, \mathrm{NaNO}_{3}$ decomposes to give $\mathrm{NaNO}_{2}$ and oxygen. $$ 2 \mathrm{NaNO}_{3} \xrightarrow{	ext { above } 500^{\circ} \mathrm{C}} 2 \mathrm{NaNO}_{2}+\mathrm{O}_{2} \uparrow $$ On further heating to above $800^{\circ} \mathrm{C}, \mathrm{NaNO}_{2}$ further decomposes to give $\mathrm{Na}_{2} \mathrm{O}, \mathrm{N}_{2}$ and $\mathrm{O}_{2}$.\ $2 \mathrm{NaNO}_{2} \xrightarrow{	ext { above } 800^{\circ} \mathrm{C}} \mathrm{Na}_{2} \mathrm{O}+\frac{3}{2} \mathrm{O}_{2} \uparrow+\mathrm{N}_{2}$\