Toluene when treated with $\mathrm{Br}_{2} / \mathrm{Fe}$ gives $p$-bromotoluene as the major produc

Question

Toluene when treated with $\mathrm{Br}_{2} / \mathrm{Fe}$ gives $p$-bromotoluene as the major product because $\mathrm{CH}_{3}$ group\

Professor PC Thomas Classes · Answer

(a, c) : Methyl group activates the benzene nucleus due to its electron releasing nature and also shows hyperconjugation. It is an ortho and para-directing group i.e., on substitution it forms always a mixture of ortho and para derivatives.\